Integrand size = 24, antiderivative size = 103 \[ \int \frac {x^3}{\left (a+b x^2\right ) \left (c+d x^2\right )^{5/2}} \, dx=-\frac {c}{3 d (b c-a d) \left (c+d x^2\right )^{3/2}}-\frac {a}{(b c-a d)^2 \sqrt {c+d x^2}}+\frac {a \sqrt {b} \text {arctanh}\left (\frac {\sqrt {b} \sqrt {c+d x^2}}{\sqrt {b c-a d}}\right )}{(b c-a d)^{5/2}} \]
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Time = 0.07 (sec) , antiderivative size = 103, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.208, Rules used = {457, 79, 53, 65, 214} \[ \int \frac {x^3}{\left (a+b x^2\right ) \left (c+d x^2\right )^{5/2}} \, dx=\frac {a \sqrt {b} \text {arctanh}\left (\frac {\sqrt {b} \sqrt {c+d x^2}}{\sqrt {b c-a d}}\right )}{(b c-a d)^{5/2}}-\frac {a}{\sqrt {c+d x^2} (b c-a d)^2}-\frac {c}{3 d \left (c+d x^2\right )^{3/2} (b c-a d)} \]
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Rule 53
Rule 65
Rule 79
Rule 214
Rule 457
Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} \text {Subst}\left (\int \frac {x}{(a+b x) (c+d x)^{5/2}} \, dx,x,x^2\right ) \\ & = -\frac {c}{3 d (b c-a d) \left (c+d x^2\right )^{3/2}}-\frac {a \text {Subst}\left (\int \frac {1}{(a+b x) (c+d x)^{3/2}} \, dx,x,x^2\right )}{2 (b c-a d)} \\ & = -\frac {c}{3 d (b c-a d) \left (c+d x^2\right )^{3/2}}-\frac {a}{(b c-a d)^2 \sqrt {c+d x^2}}-\frac {(a b) \text {Subst}\left (\int \frac {1}{(a+b x) \sqrt {c+d x}} \, dx,x,x^2\right )}{2 (b c-a d)^2} \\ & = -\frac {c}{3 d (b c-a d) \left (c+d x^2\right )^{3/2}}-\frac {a}{(b c-a d)^2 \sqrt {c+d x^2}}-\frac {(a b) \text {Subst}\left (\int \frac {1}{a-\frac {b c}{d}+\frac {b x^2}{d}} \, dx,x,\sqrt {c+d x^2}\right )}{d (b c-a d)^2} \\ & = -\frac {c}{3 d (b c-a d) \left (c+d x^2\right )^{3/2}}-\frac {a}{(b c-a d)^2 \sqrt {c+d x^2}}+\frac {a \sqrt {b} \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {c+d x^2}}{\sqrt {b c-a d}}\right )}{(b c-a d)^{5/2}} \\ \end{align*}
Time = 0.22 (sec) , antiderivative size = 100, normalized size of antiderivative = 0.97 \[ \int \frac {x^3}{\left (a+b x^2\right ) \left (c+d x^2\right )^{5/2}} \, dx=\frac {-b c^2-a d \left (2 c+3 d x^2\right )}{3 d (b c-a d)^2 \left (c+d x^2\right )^{3/2}}-\frac {a \sqrt {b} \arctan \left (\frac {\sqrt {b} \sqrt {c+d x^2}}{\sqrt {-b c+a d}}\right )}{(-b c+a d)^{5/2}} \]
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Time = 3.06 (sec) , antiderivative size = 109, normalized size of antiderivative = 1.06
method | result | size |
pseudoelliptic | \(-\frac {a b \arctan \left (\frac {b \sqrt {d \,x^{2}+c}}{\sqrt {\left (a d -b c \right ) b}}\right ) \left (d \,x^{2}+c \right )^{\frac {3}{2}} d +\frac {2 \sqrt {\left (a d -b c \right ) b}\, \left (\frac {3}{2} a \,d^{2} x^{2}+a c d +\frac {1}{2} b \,c^{2}\right )}{3}}{\left (d \,x^{2}+c \right )^{\frac {3}{2}} \sqrt {\left (a d -b c \right ) b}\, \left (a d -b c \right )^{2} d}\) | \(109\) |
default | \(\text {Expression too large to display}\) | \(1409\) |
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Leaf count of result is larger than twice the leaf count of optimal. 225 vs. \(2 (87) = 174\).
Time = 0.29 (sec) , antiderivative size = 535, normalized size of antiderivative = 5.19 \[ \int \frac {x^3}{\left (a+b x^2\right ) \left (c+d x^2\right )^{5/2}} \, dx=\left [\frac {3 \, {\left (a d^{3} x^{4} + 2 \, a c d^{2} x^{2} + a c^{2} d\right )} \sqrt {\frac {b}{b c - a d}} \log \left (\frac {b^{2} d^{2} x^{4} + 8 \, b^{2} c^{2} - 8 \, a b c d + a^{2} d^{2} + 2 \, {\left (4 \, b^{2} c d - 3 \, a b d^{2}\right )} x^{2} + 4 \, {\left (2 \, b^{2} c^{2} - 3 \, a b c d + a^{2} d^{2} + {\left (b^{2} c d - a b d^{2}\right )} x^{2}\right )} \sqrt {d x^{2} + c} \sqrt {\frac {b}{b c - a d}}}{b^{2} x^{4} + 2 \, a b x^{2} + a^{2}}\right ) - 4 \, {\left (3 \, a d^{2} x^{2} + b c^{2} + 2 \, a c d\right )} \sqrt {d x^{2} + c}}{12 \, {\left (b^{2} c^{4} d - 2 \, a b c^{3} d^{2} + a^{2} c^{2} d^{3} + {\left (b^{2} c^{2} d^{3} - 2 \, a b c d^{4} + a^{2} d^{5}\right )} x^{4} + 2 \, {\left (b^{2} c^{3} d^{2} - 2 \, a b c^{2} d^{3} + a^{2} c d^{4}\right )} x^{2}\right )}}, -\frac {3 \, {\left (a d^{3} x^{4} + 2 \, a c d^{2} x^{2} + a c^{2} d\right )} \sqrt {-\frac {b}{b c - a d}} \arctan \left (\frac {{\left (b d x^{2} + 2 \, b c - a d\right )} \sqrt {d x^{2} + c} \sqrt {-\frac {b}{b c - a d}}}{2 \, {\left (b d x^{2} + b c\right )}}\right ) + 2 \, {\left (3 \, a d^{2} x^{2} + b c^{2} + 2 \, a c d\right )} \sqrt {d x^{2} + c}}{6 \, {\left (b^{2} c^{4} d - 2 \, a b c^{3} d^{2} + a^{2} c^{2} d^{3} + {\left (b^{2} c^{2} d^{3} - 2 \, a b c d^{4} + a^{2} d^{5}\right )} x^{4} + 2 \, {\left (b^{2} c^{3} d^{2} - 2 \, a b c^{2} d^{3} + a^{2} c d^{4}\right )} x^{2}\right )}}\right ] \]
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\[ \int \frac {x^3}{\left (a+b x^2\right ) \left (c+d x^2\right )^{5/2}} \, dx=\int \frac {x^{3}}{\left (a + b x^{2}\right ) \left (c + d x^{2}\right )^{\frac {5}{2}}}\, dx \]
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Exception generated. \[ \int \frac {x^3}{\left (a+b x^2\right ) \left (c+d x^2\right )^{5/2}} \, dx=\text {Exception raised: ValueError} \]
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none
Time = 0.30 (sec) , antiderivative size = 127, normalized size of antiderivative = 1.23 \[ \int \frac {x^3}{\left (a+b x^2\right ) \left (c+d x^2\right )^{5/2}} \, dx=-\frac {\frac {3 \, a b d \arctan \left (\frac {\sqrt {d x^{2} + c} b}{\sqrt {-b^{2} c + a b d}}\right )}{{\left (b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}\right )} \sqrt {-b^{2} c + a b d}} + \frac {b c^{2} + 3 \, {\left (d x^{2} + c\right )} a d - a c d}{{\left (b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}\right )} {\left (d x^{2} + c\right )}^{\frac {3}{2}}}}{3 \, d} \]
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Time = 5.67 (sec) , antiderivative size = 110, normalized size of antiderivative = 1.07 \[ \int \frac {x^3}{\left (a+b x^2\right ) \left (c+d x^2\right )^{5/2}} \, dx=\frac {\frac {c}{3\,\left (a\,d-b\,c\right )}-\frac {a\,d\,\left (d\,x^2+c\right )}{{\left (a\,d-b\,c\right )}^2}}{d\,{\left (d\,x^2+c\right )}^{3/2}}-\frac {a\,\sqrt {b}\,\mathrm {atan}\left (\frac {\sqrt {b}\,\sqrt {d\,x^2+c}\,\left (a^2\,d^2-2\,a\,b\,c\,d+b^2\,c^2\right )}{{\left (a\,d-b\,c\right )}^{5/2}}\right )}{{\left (a\,d-b\,c\right )}^{5/2}} \]
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